Last updated on July 14th, 2025
We use the derivative of e^3x, which is 3e^3x, as a measuring tool for how the exponential function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of e^3x in detail.
We now understand the derivative of e^3x. It is commonly represented as d/dx (e^3x) or (e^3x)', and its value is 3e^3x. The function e^3x has a clearly defined derivative, indicating it is differentiable for all real numbers. The key concepts are mentioned below: Exponential Function: e^3x is an exponential function with a base of e and a coefficient 3 in the exponent. Chain Rule: Rule for differentiating composite functions like e^3x. Natural Exponential Function: The base of the natural exponential function is e, an important constant approximately equal to 2.71828.
The derivative of e^3x can be denoted as d/dx (e^3x) or (e^3x)'. The formula we use to differentiate e^3x is: d/dx (e^3x) = 3e^3x The formula applies to all x as the exponential function is defined for all real numbers.
We can derive the derivative of e^3x using proofs. To show this, we will use the rules of differentiation. There are several methods we use to prove this, such as: Using Chain Rule We will now demonstrate that the differentiation of e^3x results in 3e^3x using this method: Using Chain Rule To prove the differentiation of e^3x using the chain rule, Consider f(x) = e^u and u = 3x By the chain rule: d/dx [f(u)] = f'(u) · u' Let’s substitute f(u) = e^u and u = 3x, d/dx (e^3x) = e^3x · (d/dx (3x)) d/dx (e^3x) = e^3x · 3 Thus, we have, d/dx (e^3x) = 3e^3x. Hence, proved.
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky. To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like e^3x. For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x) Similarly, the third derivative, f′′′(x) is the result of the second derivative and this pattern continues. For the nth Derivative of e^3x, we generally use fⁿ(x) for the nth derivative of a function f(x) which tells us the change in the rate of change. (continuing for higher-order derivatives).
When x is any real number, the derivative of e^3x is always defined. For example, when x is 0, the derivative of e^3x = 3e^0, which is 3.
Students frequently make mistakes when differentiating e^3x. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (e^3x · x^2)
Here, we have f(x) = e^3x · x^2. Using the product rule, f'(x) = u′v + uv′ In the given equation, u = e^3x and v = x^2. Let's differentiate each term, u′ = d/dx (e^3x) = 3e^3x v′ = d/dx (x^2) = 2x Substituting into the given equation, f'(x) = (3e^3x) · (x^2) + (e^3x) · (2x) Let's simplify terms to get the final answer, f'(x) = 3x^2e^3x + 2xe^3x Thus, the derivative of the specified function is 3x^2e^3x + 2xe^3x.
We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.
A company models its revenue growth with the function R(x) = e^3x, where x is the time in years. Calculate the rate of revenue growth at x = 2 years.
We have R(x) = e^3x (revenue growth model)...(1) Now, we will differentiate the equation (1) Take the derivative e^3x: dR/dx = 3e^3x Given x = 2 (substitute this into the derivative) dR/dx = 3e^(3*2) = 3e^6 Hence, the rate of revenue growth at x = 2 years is 3e^6.
We find the rate of revenue growth at x = 2 years as 3e^6, which represents how the revenue is expected to increase exponentially after 2 years.
Derive the second derivative of the function y = e^3x.
The first step is to find the first derivative, dy/dx = 3e^3x...(1) Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [3e^3x] d²y/dx² = 3 · 3e^3x d²y/dx² = 9e^3x Therefore, the second derivative of the function y = e^3x is 9e^3x.
We use the step-by-step process, where we start with the first derivative. We then differentiate it once more to find the second derivative, which is 9e^3x.
Prove: d/dx (e^6x) = 6e^6x.
Let's start using the chain rule: Consider y = e^6x To differentiate, we use the chain rule: dy/dx = e^6x · d/dx (6x) Since the derivative of 6x is 6, dy/dx = 6e^6x Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation. We then replace the derivative of the exponent and simplify to derive the equation.
Solve: d/dx (e^3x/x)
To differentiate the function, we use the quotient rule: d/dx (e^3x/x) = (d/dx (e^3x) · x - e^3x · d/dx(x)) / x² We will substitute d/dx (e^3x) = 3e^3x and d/dx(x) = 1 = (3e^3x · x - e^3x · 1) / x² = (3xe^3x - e^3x) / x² = e^3x(3x - 1) / x² Therefore, d/dx (e^3x/x) = e^3x(3x - 1) / x²
In this process, we differentiate the given function using the quotient rule. As a final step, we simplify the equation to obtain the final result.
Derivative: The derivative of a function indicates how the given function changes in response to a slight change in x. Exponential Function: A mathematical function in the form of f(x) = a^x, where a is a constant and x is an exponent. Chain Rule: A rule for differentiating composite functions, allowing us to differentiate nested functions. Product Rule: A differentiation rule used to find the derivative of the product of two functions. Quotient Rule: A differentiation rule used to find the derivative of the quotient of two functions.
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